We are creating a new card game with a new deck. Unlike the normal deck that has

Question

We are creating a new card game with a new deck. Unlike the normal deck that has 13 ranks (Ace through King) and 4 Suits (hearts, diamonds, spades, and clubs), our deck will be made up of the following.

Each card will have:
i) One rank from 1 to 12.
ii) One of 9 different suits.

Hence, there are 108 cards in the deck with 12 ranks for each of the 9 different suits, and none of the cards will be face cards! So, a card rank 11 would just have an 11 on it. Hence, there is no discussion of "royal" anything since there won't be any cards that are "royalty" like King or Queen, and no face cards!

The game is played by dealing each player 5 cards from the deck. Our goal is to determine which hands would beat other hands using probability. Obviously the hands that are harder to get (i.e. are more rare) should beat hands that are easier to get.

How many different ways are there to get a straight flush (cards go in consecutive order like 4, 5, 6, 7, 8 and all have the same suit. Also, we are assuming there is no wrapping, so you cannot have the ranks be 10, 11, 12, 1, 2)?

Explanation / Answer

The straight flush of cards can be any one of the following sets 12345,23456,34567,45678,56789,678910,7891011,89101112 i.e.

8 possibilities and all the cards belonging to same suit can be selected in C(9,1) ways

Thus total num of ways are 8C1 * 9C1 =72 ways'

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