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given commands from an air traffic controller. The reactions times for each grou

ID: 3125292 • Letter: G

Question

given commands from an air traffic controller. The reactions times for each group of pilots is below. The researcher is interested in learning if the drug reduces the reaction time. Her hypothesis is: The mean reaction time in group A will be less than the mean in group B. Group A Treated with Drug 0.72, 0.68, 0.69, 0.66, 0.57,0.66, 0.7, 0.63, 0.71, 0.73 Group B Control- Not Treated 0.71, 0.83, 0.89, 0.57, 0.68, 0.74, 0.75, 0.67, 0.8, 0.78 A t-test can be used to test the probability that the two means do not differ. The alternative is that the reaction times from the group treated with the drug will not be less than that from the control group. This is a one-tailed test because the researcher is interested in if the drug decreased reaction time. She is not interested in if the drug changed reaction time.

-Background of problem

-justify type of t-Test used

- justify type of test (directional/non-directional)

- identify alpha level used to test the null hypothesis Results

- Report descriptive statistics

- Assess normality assumption

- Levine’s Test for Homogeneity of Variance

- Assess equal variance assumption decision:

Explanation / Answer

Here the researcher is interested in knowing whether the drug reduces the reaction time.Here the researcher is interested in one tailed hypothesis.Here there are two groups namely grop A and B.Group A Treated with Drug,Group B Control- Not Treated.

Here as the two grops are independent of each other independent sample t-test is used.

Here one directional t-test is used because the researcher is interested in if the drug decreased reaction time.The researcher is not interested in if the drug changed reaction time.Hence two tailed t-test is not used.

Here we can use 5% level of significance as alpha as alpha level is not mentioned.

Descriptive statistics:

Group Statistics                  
Group N Mean   Std. Deviation
A 10   .6750   .04790
B 10   .7420   .09077   

Here Mean of group A is = 2 times the standard deviation

Also Mean of group B is = 2 times the standard deviation . Hence the two groups follows normal distribution.

Levene's Test is used to test variances of the populations from which different samples are drawn are equal.

It tests the null hypothesis that the population variances are equal (called homogeneity of variance or homoscedasticity).

Here for this data Leven's F test =2.588, P value=0.125>0.05 Hence population variances of the two groups are equal.