Joan invested $8000.Part was invested at 8% and the rest was invested at 6%. If

Question

Joan invested $8000.Part was invested at 8% and the rest was invested at 6%. If thetotal interest was $580, Find how much was invested at eachpercent. I tried doing 2 times with 4 different equations. 1) x+y=8000 0.08x+0.06=580 my answer for x was 26900 and y was-18900 2)x+y=580 0.08x+0.06y=8000 my answer for x was 401740 and y was-401160 i think both answers are wrong since both equations arewrong could you please help me? Joan invested $8000.Part was invested at 8% and the rest was invested at 6%. If thetotal interest was $580, Find how much was invested at eachpercent. I tried doing 2 times with 4 different equations. 1) x+y=8000 0.08x+0.06=580 my answer for x was 26900 and y was-18900 2)x+y=580 0.08x+0.06y=8000 my answer for x was 401740 and y was-401160 i think both answers are wrong since both equations arewrong could you please help me? I tried doing 2 times with 4 different equations. 1) x+y=8000 0.08x+0.06=580 my answer for x was 26900 and y was-18900 2)x+y=580 0.08x+0.06y=8000 my answer for x was 401740 and y was-401160 i think both answers are wrong since both equations arewrong could you please help me?

Explanation / Answer

A: money at 8% B: money at 6% 1.08 A +1.06 B = 8580 A+B = 8000 108A+106B=858000 (100* 1st row -> 1st row) A+B=8000 A-B=2000                (-107* 2nd row+1st row->1st row) A+B=8000 A-B=2000              (-1 1st row+2nd row ->2nd row) 2B=6000 B=3000 A-3000=2000     (replacing) A=5000 B=3000 , A=5000

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