Question No 1: solve each part of the simultanousequation. a) a belt and wallet
ID: 3092906 • Letter: Q
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Question No 1: solve each part of the simultanousequation. a) a belt and wallet cost $ 42 while 7 beltsand 4wallets cost $213. calculate the cost of each. b) $2500 is to be deposited in Banks A and B. Theinterests rate per annum of Bank A is 6% while that forB ank B is 6 1/2 %. After one year , their interestsare equal . How much money is to be deposited ineach bank??/ Question No 1: solve each part of the simultanousequation. a) a belt and wallet cost $ 42 while 7 beltsand 4wallets cost $213. calculate the cost of each. b) $2500 is to be deposited in Banks A and B. Theinterests rate per annum of Bank A is 6% while that forB ank B is 6 1/2 %. After one year , their interestsare equal . How much money is to be deposited ineach bank??/Explanation / Answer
I can help you with part A. let b stand for belts let w stand for wallets this is the information you are given: b + w = $42 7b + 4w = $213 if you move w to the other side of the equal sign in the firstequation, then b=-w + 42 now you can substitute b for -w+42 in the second equation to findthe value of w as shown: 7b + 4w =213 - subsistute -w+42 for b 7(-w+42) +4w =213 - factor out 7(-w+42) -7w + 294 + 4w = 213 - simplify -3w +294 =213 - subtract 294 from both sides -3w =-81 - divide -3 from both sides w = 27 now that you know the value of w, you can plug it into either ofthe original equations to find the value of b as shown: b+w=42 -substitute 27 for w or 7b+4w=213 -substitute 27 for w b+27=42 - subtract27 from bothsides 7b+4(27)=213 -simplify b=15 7b+108=213 -subtract 108 from both sides 7b=105 -divide both sides by 7 b=15 they both equal 15! :) and if you want to check: 15 + 27=42 and 7(15) + 4(27) = 213 42=42yay! 105 + 108 = 213 213 = 213 yay! wallets are $27 and belts are $15 i hope this helps! :)
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