0 ezto.mheducation.com o do Assignments: SP2018 - STAT 302 OL: Q.. Chapter 9 - S

Question

0 ezto.mheducation.com o do Assignments: SP2018 - STAT 302 OL: Q.. Chapter 9 - Sections 1 and 2 Connect Pr... Chegg Study Guided Solutions and St... Recall That "very satisfied" Customer.. Recall That "very Satisfied" Customer.. + Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 68 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting y represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis Ho and the alternative hypothesis He needed if we wish to attempt to provide evidence supporting the claim that p exceeds 42. Ho: p( (Click to select) 4 42 versus Ha:p ( (Click to select) 4 42. (b) The random sample of 68 satisfaction ratings yields a sample mean of X= 42.810. Assuming that o equals 2.70, use critical values to test Ho versus H, at each of a = .10, .05, .01, and .001. (Round your answer z,05 to 3 decimal places and other z-scores to 2 decimal places.) z= Rejection points Z.10 2.05 Z.01 2.001 Reject H, with a= [(Click to select) A, but not with a = (Click to select) A (c) Using the information in part (b), calculate the p-value and use it to test H, versus H, at each of a = 10, .05, .01, and .001. (Round your answers to 4 de places.) p-value = Since p-value = is less than (Click to select) 9; reject H, at those levels of a but not with a= (Click to select) 9. (d) How much evidence is there that the mean composite satisfaction rating exceeds 42? There is (Click to select) a evidence.

Explanation / Answer

Answer to the question is as follows:

a. Ho: Mu < = 42

Ha: Mu > 42

b. z = (42.81 - 42)/(2.7/sqrt(68)) = 2.47

c.

Rejection points:

z.10= 1.28

z.05= 1.645

z.01= 2.325

z.001 = 3.08

d. p-value for Z>2.47 is 0.0067 is less than .01: reject Ho at those levels of alpha but not with alpha = .001

There is enough evidence

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.