0 T13)100 3/29/2018 02:10 AM Print Calculator Periodic Table Gradeb Question 7 o

Question

0 T13)100 3/29/2018 02:10 AM Print Calculator Periodic Table Gradeb Question 7 of 10 Sapling Learning A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in Figure A, she rotates about her center of mass at a rate of 5.91 rad/s. Her moment of inertia about this axis is 19.7 kg m2. A short time later the aerialist is in the straight position, as shown in Figure B. If the moment of inertia about her center of mass in this position is now 31.3 kg-m2, what is her rotational speed? Number rad/s Figure B Figure A

Explanation / Answer

Using Angular momentum conservation:

Li = Lf

Ii*wi = If*wf

wf = wi*(Ii/If)

Ii = initial moment of inertia = 19.7 kg-m^2

wi = initial angular velocity = 5.91 rad/sec

If = final moment of inertia = 31.3 kg-m^2

wf = final angular velocity = ? rad/sec

So,

wf = 5.91*(19.7/31.3)

wf = 3.72 rad/sec

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