Examine these data for shape, center, spread and outliers. The normal quartile p

Question

Examine these data for shape, center, spread and outliers. The normal quartile plot indicates the distribution is reasonably Normal except for one outlier in each direction. Because these are not extreme and preserve the symmetry of the distribution, use of the t procedures is safe with 44 observations. Safari File Edit View History Bookmarks Window Help ID webassign.net SPRING FSTC 481 901 Your last submission is used for your score 1. O3/S points | Previous Answers My Great white sharks are big and hungry. Here are the lengths in feet of 44 great whites. 18.7 12.3 18.5 16.5 15.8 18.5 14.7 15.9 14.9 17.7 12.2 16.2 16.7 17.9 16.0 12.6 17.7 13.6 12.1 15.3 14.7 12.6 13.1 15.8 14.5 16.4 9.4 18.3 13.0 13.5 15.5 16.0 13.4 19.1 16.1 22.716.7 13.7 13.1 15.6 19.9 18.5 13.3 16.7 Follow the JMP steps below for this question. 1. Open JMP, click File> New> Data Table. This will open a new data table with one column named Column 1. Double-click at the variable name Column 1 and rename it to Length 2. Move the cursor to highlight and copy these data. Next, at the JMP table, point and click at the first row under the variable and paste data values into this 3. Click Analyze> Distribution, select Length for Y Columns and click OK 4. On the output window, click the red triangle besides the variable Length and select Normal Quantile Plot 5. Read the Summary of Statistics (no calculation needed) at the output window to find answers for parts (a), (b), and (c). Examine these data for shape, center, spread and outliers. The normal quantile plot indicates the distribution is reasonably Normal except for one outlier in each direction. Because these are not extreme and preserve the symmetry of the distribution, use of the t procedures is safe with 44 observations. (a) Find the sample mean and sample standard deviation x- 15.58 s 2.550 (b) The standard error of sample mean is ft (Round to 2 decimal places.) ft (Round to 3 decimal places.) SE(x) 384 ft. (Round to 3 decimal places) (c) Use these data to give a 9S% confidence interval for the mean length of all great white sharks. 15.20 X to 15.96 x ft (Round to 2 decimal places.)

Explanation / Answer

Solutionc:

code in R to get the 95% confoidence interval with te.test function.

cretae a vector in R named whitesharks .

Run below code:

Whitesharks <- c(18.7,12.3,18.5,16.5,15.8,18.5,14.7,15.9,14.9,17.7,12.2,16.2,16.7,17.9,16.0,12.6,17.7,13.6
,12.1,15.3,14.7,12.6,13.1,15.8,14.5,16.4,9.4,18.3,13,13.5,15.5,16,
13.4,19.1,16.1,22.7,16.7,13.7,13.1,15.6,19.9,18.5,13.3,16.7)

t.test(Whitesharks)

Output:

One Sample t-test

data: Whitesharks
t = 40.527, df = 43, p-value < 2.2e-16
alternative hypothesis: true mean is not equal to 0
95 percent confidence interval:
14.80213 16.35242
sample estimates:
mean of x
15.57727

Form output:

95 percent confidence interval:
14.80 and 16.35

ANSWER:14.80 to 16.35

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