PLEASE DONT ANSWER UNLESS YOU ANSWER ALL PARTS..... THANKS IN ADVANCE Homework:

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PLEASE DONT ANSWER UNLESS YOU ANSWER ALL PARTS.....

THANKS IN ADVANCE

Homework: HW 2 Save Score: 0 of 1 pt 41 of 41 (29 complete) HW Score: 64.77%, 26.56 of 41 pts 0.3.11 Question Help * The accompanying technology output was obtained by using the paired data consisting of foot lengths (cm) and heights (cm) of a sample of 40 people. Along with the paired sample data, the technology was also given a foot length of 16.2 cm to be used for predicting height. The technology found that there is a linear correlation between height and foot length. If someone has a foot length of 16.2 cm, what is the single value that is the best predicted height for that person? Click the icon to view the technology output. The single value that is the best predicted height is cm Round to the nearest whole number as needed.)

Explanation / Answer

10.3.11.

Line of Regression Y on X i.e Y = bo + b1 X

calculation procedure for regression

mean of X = X / n = 964.1667

mean of Y = Y / n = 78.15

(Xi - Mean)^2 = 69876.83334

(Yi - Mean)^2 = 211.96

(Xi-Mean)*(Yi-Mean) = 3657.85001

b1 = (Xi-Mean)*(Yi-Mean) / (Xi - Mean)^2

= 3657.85001 / 69876.83334

= 0.05235

bo = Y / n - b1 * X / n

bo = 78.15 - 0.05235*964.1667 = 27.67866

value of regression equation is, Y = bo + b1 X

Y'=27.67866+0.05235* X

predicted temprature when 3000,

Y' = 27.67866+0.05235* 3000 = 184.72866

Q. 10.2.27

Line of Regression Y on X i.e Y = bo + b1 X

calculation procedure for regression

mean of X = X / n = 12.7143

mean of Y = Y / n = 39.9429

(Xi - Mean)^2 = 477.16854

(Yi - Mean)^2 = 4710.52

(Xi-Mean)*(Yi-Mean) = 1499.23569

b1 = (Xi-Mean)*(Yi-Mean) / (Xi - Mean)^2

= 1499.23569 / 477.16854

= 3.14194

bo = Y / n - b1 * X / n

bo = 39.9429 - 3.14194*12.7143 = -0.00469

value of regression equation is, Y = bo + b1 X

Y'=-0.00469+3.14194* X

the predicted value when diameter of 45.6 ,

Y'=-0.00469+3.14194* X

Y'=-0.00469+3.14194* 45.6

Y'= 143.267774

Q 10.2.13

Line of Regression Y on X i.e Y = bo + b1 X

calculation procedure for regression

mean of X = X / n = 52.6667

mean of Y = Y / n = 384.5

(Xi - Mean)^2 = 149.33334

(Yi - Mean)^2 = 25511.5

(Xi-Mean)*(Yi-Mean) = 1789

b1 = (Xi-Mean)*(Yi-Mean) / (Xi - Mean)^2

= 1789 / 149.33334

= 11.97991

bo = Y / n - b1 * X / n

bo = 384.5 - 11.97991*52.6667 = -246.44234

value of regression equation is, Y = bo + b1 X

Y'=-246.44234+11.97991* X

predicted value when weight of a bear with a chest size of 45 inch,

Y'=-246.44234+11.97991* 45 = 292.65361

and for 10.3.11 we could not able to see the table data to answer the question..

X Y (Xi - Mean)^2 (Yi - Mean)^2 (Xi-Mean)*(Yi-Mean) 1042 81.6 6058.02259 11.9025 268.52488 836 73.2 16426.70299 24.5025 634.42517 986 78.1 476.69299 0.0025 -1.09167 887 76.2 5954.69959 3.8025 150.47507 1150 89 34534.01539 117.7225 2016.29131 884 70.8 6426.69979 54.0225 589.22525

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