2, (16 points) Assume that a student has enjoyed 84% of all the classes he has t
ID: 3057295 • Letter: 2
Question
2, (16 points) Assume that a student has enjoyed 84% of all the classes he has taken at AUS. After he starts working part time as a student worker at the Dean's office, he works on a survey which lets him access to faculty evaluations. From this data, he finds out that, he did not enjoy 9 % of the courses that were taught by professors with good evaluations. Also, 70% of the courses he has taken were taught by professors with good evaluations a. What is the probability that the class was taught by a professor with good evaluations and that the student did not enjoy the class? What is the probability that the class was taught by a professor with poor evaluations and that the student enjoyed the class? What is the probability that the student had a professor with good evaluations if he did not enjoy the class? Suppose that a student signed up for three courses next semester, all of which are taught by professors with poor evaluations. What is the probability he enjoys all of them? b. c. d.Explanation / Answer
here let good evaluation =P(G) and student enjoyed=P(E)
therefore from above P(E)=0.84 ; P(Ec|G) =0.09 ; P(G)= 0.70
a)P(good evaluation and did not enjoy) =P(G n Ec) =P(G)*P(Ec|G) =0.7*0.09=0.063
b) here P(G n E) =P(G)-P(G n Ec) =0.7-0.063 =0.637
hence P(poor evaluation and student enjoyed) P(Gc n E)=P(E)-P(G n E) =0.84-0.637=0.203
c)
P(G|Ec) =P(G n Ec)/P(Ec) =0.063/(1-0.84)=0.39375
d) P(enjoying course given that taught by professor of poor evaluation)=P(E|Gc) =P(E n Gc)/P(Gc) =0.203/0.3
=0.6767
hence P(he enjoy all 3 given taught by professor of poor evaluation) =(0.6767)3 =0.3098
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.