2)A single slit diffraction pattern is observed on a screen. The distance from t

Question

2)A single slit diffraction pattern is observed on a screen. The distance from the slit to the screen is 0.8m. The distance from the central maximum to the first minimum is 0.9 cm. We know the wavelength of the laser light is 632nm. What is the width of the slit in mm?

3)A single slit diffraction pattern is observed on a screen. The width of the slit is 0.02 mm. The distance from the slit to the screen is 1 m. If the wavelength of the laser light is 632.8 nm. How far is the third minimum from the central maximum in cm?

4)A single slit diffraction pattern is observed on a screen. The width of the slit is 0.02 mm. The distance from the slit to the screen is 1 m. If the wavelength of the laser light is 532 nm. How far is the second minimum to the first minimum in cm?

Explanation / Answer

part 2 )

d*y/D = m*lambda

d = lambda * D/y

d = 632 x 10^-9 * 0.8 / 0.9 x 10^-2

d = 5.62 x 10^-5 m

d = 0.0562 x 10^-3 m = 0.0562 mm

part 2 )

y = m*lambda * D/d

y = *3*632.8 x 10^-9 x 1 / 0.02 x 10^-3

y = 9.492 cm

part 3 )

m = 1

y = lambda*D/d

y = 2.66 cm

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