2) approximately what will his speed when he is at the top of his trajectory 3)

Question

2) approximately what will his speed when he is at the top of his trajectory
3) what will be the maximum height H above the ramps ?
9) what will be the time of his flight ? Given that his initial speed is 90 mph, which of the following is approximately equal to Gobble Maddison's initial velocity vector in m/s? Remember to convert mph to m/s given the conversion factor on the first page. Assume a coordinate system in which right is positive and up is positive. Present your reasoning. (-20, 20) (-15, 6.37) (-37, 15.6) (-82, 35) (20, -20)

Explanation / Answer

90 mph = 90*044704 = 40.2336 m/s

angle = 23 degrees

Vx= 40.2336cos23 = -37.035 m/s (negative because its in negative x direction)

Vy = 40.2336 sin23 = 15.72 m/s

2) at the top of trajectory his speed will be vx = 37.035 m/s

3) maximum height = Vy^2 / 2g = 12.61 m above the ramp

4) time of flight = 2Vy / g = 3.21 sec

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