5. ANOVA calculations and rejection of the null hypothesis Aa Aa The following t

Question

5. ANOVA calculations and rejection of the null hypothesis Aa Aa The following table summarizes the results of a study on SAT prep courses, comparing SAT scores of students in a private preparation class, a high school preparation class, and no preparation class. Use the information from the table to answer the remaining questions. Number of Sum of Treatment Private prep class High school prep class No prep class Observations Sample Mean Squares (SS) 690 680 640 40 40 40 175,500.00 182,520.00 200,070.00 Using the data provided, complete the partial ANOVA summary table that follows. (Hint: T, the treatment total, can be calculated as the sample mean times the number of observations. G, the grand total, can be calculated from the values of T once you have calculated them.) Source Between treatments Within treatments Sum of Squares (SS) df Mean Square (MS)

Explanation / Answer

1st option is correct

( please provide options if available for below fill in the blanks

in ANOVA the F test statistics is the ratio of the between -treatment............the value of the F test statisic is 0.151

when the null hypothesis is true; the F test statistic is 1. when the .............is most likely greater than 3.07. In general yu should reject the null hypothesis for F>3.07

Grade ni x?i S2i ni*(Xi-Xgrand)2 (ni-1)*S2i private prep 40 690.0000 175500.0000 16000.000 6844500.00 high school 40 680.0000 182520.0000 4000.000 7118280.00 no prep 40 640.0000 200070.0000 36000.000 7802730.00 670.00 56000.000 21765510.00 SSTr SSE

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