5. A square wire loop with 3.00 loop in the field, as shown below. The loop cont

Q: 5. A square wire loop with 3.00 loop in the field, as shown below. The loop cont

a) Induced emf E=-NA(dB/dt) E=-1*32*[(d/dt)(5t-1.6t2) E=-9(5-3.2t) at t =2 s E=-9(5-3.2*2) E=12.6 Volts b) Net emf at t=2 s Enet =30+12.3=42.6 Volts c) Counter clockwise d) I=E/R=42.6/21 I=2.028 A

ID: 1796130 • Letter: 5

Question

5. A square wire loop with 3.00 loop in the field, as shown below. The loop contains a 30.0 volt battery with a 21.0 ohm resistance in the circuit If the magnitude of the field varies with time according to B (5.00 T/s)t - (1.60 T/s)*t m sides is perpendicular to a uniform magnetic field, with half the area of the a. What is the induced emf in the circuit at 2.00 seconds? b. What is the total emf in the circuit at 2.00 seconds? c. What is the direction of the total current at that time (2 seconds)? d. What is the total current at that time (2 seconds)? ob000000000OOogO 00000 dOOOO0B0O00 0000OO

Explanation / Answer

Induced emf

E=-NA(dB/dt)

E=-1*32*[(d/dt)(5t-1.6t2)

E=-9(5-3.2t)

at t =2 s

E=-9(5-3.2*2)

E=12.6 Volts

Net emf at t=2 s

Enet =30+12.3=42.6 Volts

Counter clockwise

I=E/R=42.6/21

I=2.028 A

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5. A square wire loop with 3.00 loop in the field, as shown below. The loop cont

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