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19 of 30 (18 complete) This Test: 30 pts possible This Question: 1 pt Each of ta

ID: 3053121 • Letter: 1

Question

19 of 30 (18 complete) This Test: 30 pts possible This Question: 1 pt Each of tao parents has the genotype blue/green, which consists of the pair of alleles that determine eye oolor, and each parent conributes one of those aleles to a chid. Assume that f the child has at least one blue allele, that color will dominate and the child's eye color will be blue a. List the different possible outcomes. Assume that these outcomes are equaly lkely b. What is the probability that a child of these parents will have the green/green genotype? c. What is the probability that the child will have biue eye color? a.List the possible ouncomes O A. blue/blue,blue/green, and green/green B biue/blue and green/gree O C. blue/biue, blue/green, green /blue, and green/green OD, ls! tín /geen and green /blue b. The probablity that a child of these parents wilbhave the green/green genotype is Roound to two decimal places as needed.) c. The probability that the child wil have blue eye color is Round to two decimal places as needed ) Click to select your answers Type here to search 6

Explanation / Answer

Solution:-
a. option A. blue/blue, blue/green, green/blue, and green/green

b. The probability that a child of these parents will have the green/green 1/4 = 0.25

c. The probability that the child will have blue eye color is 3/4 = 0.75

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