The average yearly rainfall in the Sahara desert uned to be 10 inches. A climato

Question

The average yearly rainfall in the Sahara desert uned to be 10 inches. A climatologist believes that amount has changed. Which represent the null and aiternative hypothesis? The dimatologist takes a sample of 20 recent yearl raintatl ecords and ottains an average of 10.3 nches Suose the dets are unimodal nd spproximately ymntiric, with no ouies, and 1, 59 find the sample statistic for the ourrent everage yearty rall ??nple statistic . 1 The degrees of freedom are degrees of freedom Find the p-value. p-value What is our decision if alpha-0.08 outlers, and t-1.597 (2 decimal places) (whole number) (3 decimal places) Reject null hypothest. There s insumoent evidence that the average yerty renal has charged. Faa to repect the mall hypothesis. There "insumeert eviwee that the average yeary rainfal has denged. Re)ect te m. hypothes". There " smeert evidence that the average yer y rainta has ch d o Fail to reject the null hypothesis. There is sufficient evidence that the average yearly rainfall has changed Complete the following sentence The confidence interval corresponding to this test would be a % confidence interval, e rten"'O determine whether or not ehe nu" hypothesis should be epected what nner-odd you ick for , the confidence interval, we can also reach the same conclusion by earning ? con (whole number) Suppose we did a right-tailed test instead of this one. What would the new p-value be p-value (3 decimal places

Explanation / Answer

Answer here:

Ho: Mu = 10
Ha: Mu !=10

n= 20, sample avg = 10.3, t = 1.597

Sanmple statistic = 1.60

df = n-1 = 20-1 = 19

p-value is P(|t|>1.597) = .1268

The decision is : Fail to reject the null hypothesis: There is insufficient evidence that the average yearly rainfall has changed

The confidence interval corresonding to the this test would be 87.32 % confidence interval.

I would look for 0 in the confidence interval if I do not want to reject Ho. It would mean that
that the Ho stands not rejected for lack of evidence

New p-value is half of what we have now. i.e. 0.063

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.