The average surface temperature on Venus is 737K and the average pressure is abo

Question

The average surface temperature on Venus is 737K and the average pressure is about 9.2MPa

A) Calculate the number of particles in one unit of volume of Venus "air" on its surface

B) Assuming that the atmospher of Venus is a monoatomic ideal gas (although) it is not, how much thermal energy is there in one unit volume of Venus "air"? How many Lindt Bittersweet bars is this?

C) For normal atmospheric pressure at sea level, calculate the number of particles in one unit volume of classroom air. Compar this number with that on venus

D) Calculate the thermal energy in one unit volume of classroom air at the temperature of about 300K, again making the assuumption that it is a monoatomic ideal gas. How does this result compare with that at part B?

E) Calculate the "average" speed of a particle in one unit volume of Venus "air" and classroom air. Assuming that Venus' atmospher is entirely made of CO2 molecules and that our classroom air is made entirely of Nitrogen molecules.

A few hints:

You will need to use the Ideal Gas Law in the appropriate form

An ideal gas has three degrees of freedom.

Eating one bar of Lindt bittersweet chocolate, gives your body 210 Cal, which is 210 X 1000 X 4.186J = 9.73 X105 J

Explanation / Answer

a) P V = N k T

N/V = P/(kT) = 9.2E6/(1.38E-23*737)= 9.05E26

b) U = 3/2 N k T

U/V = 3/2 N/V k T

U/V = 1.5*9.05E26*1.38E-23*737= 1.38E7 J

each bar has 9.73E5

so number = 1.38E7/9.73E5= 14.18

c)

N/V = P/(kT) = 1.013E5/(1.38E-23*295)= 2.49E25

d)

U/V = 3/2 N/V k T = 1.5*2.49E25*1.38E-23*295= 1.52E5

about 100 times smaller than B)

E)

so 1/2 mv^2 = 3/2 k T
on venus
v = sqrt( 3 kT/m) = sqrt(3*1.38E-23*838/2.32E-26)= 1223 m/s

in the classroom

v = sqrt(3*1.38E-23*300/2.32E-26)= 732 m/s

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