In response to the increasing weight of airline passengers, the Federal Aviation

Question

In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume that passengers average 193 pounds in the summer, including clothing and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 37 pounds. Weights are not Normally distributed, especially when the population includes both men and women, but they are not very non- Normal. A commuter plane carries 20 passengers. What is the approximate probability that the total weight of the passengers exceeds 4260 pounds? (Round your answer to four decimal places.) + "M points MBasicStat7 15·E.037. My Notes Ask Your Teache To estimate the mean score of those who took the Medical College Admission Test on your campus, you will obtain the scores of an SRS of students. From published information, you know that the scores are approximately Normal with standard deviation about 3.6. How large an SRS must you take to reduce the standard deviation of the sample mean score to 1? (Round your answer up to the next whole number.) students

Explanation / Answer

1) Solution:

The approximate probability is that the total weight of the passengers exceeds 4260 pounds is,
First, compute the z-score then find probability based on standard normal table.
x = 4260/20
= 213
For x = 213 converts to
z = x- /
= 213 - 193/37
= 0.54
From the standard normal distribution table, the associated probability is

P(z > 0.54) = 1P ( Z<0.54 )
= 10.7054
= 0.2946
The approximate probability is that the total weight of the passengers exceeds 4260 pounds is 0.2946

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