In response to the increasing weight of airline passengers, the Federal Aviation

Question

In response to the increasing weight of airline passengers, the Federal Aviation Administration in 2003 told airlines to assume that passengers average 190.1 pounds in the summer, including clothing and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 37.9 points. Weights are normally distributed. especially when the population includes both men and women, but they are not very non-Normal. A commuter plane carries 24 passengers. What is the approximate probability (plus or minus 0.0001) that the total weight of the passengers exceeds 4953 pounds?

Explanation / Answer

P(xbar > 4953/24)

= P(xbar > 206.375)

= P(z > (206.375 - 190.1) / (37.9/sqrt(24)))

= P(z > 16.275/185.67>0.08)

= 1 - .9948

= .0052

There is a 0.52% chance that the total weight of the passengers exceeds 4,953 lbs P(xbar > 4953/24)

= P(xbar > 206.375)

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.