A certain brand of automobile tire has a mean life span of 35,000 miles and a st

Question

A certain brand of automobile tire has a mean life span of 35,000 miles and a standard deviation of 2,050 miles (assume the life spans of the tires have a bell shaped distribution)
the life span of three randomly selected tires are 38,000 34,000 31,000 miles. Find the z-score that corresponds to each life span. A certain brand of automobile tire has a mean life span of 35,000 miles and a standard deviation of 2,050 miles (assume the life spans of the tires have a bell shaped distribution)
the life span of three randomly selected tires are 38,000 34,000 31,000 miles. Find the z-score that corresponds to each life span. A certain brand of automobile tire has a mean life span of 35,000 miles and a standard deviation of 2,050 miles (assume the life spans of the tires have a bell shaped distribution)
the life span of three randomly selected tires are 38,000 34,000 31,000 miles. Find the z-score that corresponds to each life span.

Explanation / Answer

= 35000

= 2050

Z = (X - ) /

Z-score for 38000 = (38000 - 35000) / 2050 = 1.46

Z-score for 34000 = (34000 - 35000) / 2050 = -0.49

Z-score for 31000 = (31000 - 35000) / 2050 = -1.95

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