1. What is your conclision about Solution X as an inhibitor? Include whether you

Question

1. What is your conclision about Solution X as an inhibitor? Include whether you think it is a competitive or non-competitive inhibitor (or neither) and why?

2. What is your conlusion about Solutino Y as an inhibitor? Include whether you think it is a competitive or non-competitive inhibitor (or neither) and why?

3. What was the purpose of the tube that jsut had a high concentratino of ONPG, but no inhibitors?

Absorbance at 450nm 500ul ONPG + No inhibitor Time (min) 0.5 1.5 1000?? ONPG + No inhibitor 500?? ONPG + Inhibitor X 1000?! ONPG + Inhibitor X 500ul ONPG + Inhibitor Y 1000ul ONPG + Inhibitor Y 0 0.03 0.065 0.1 0.133 0.039 0.089 0.14 0.188 0.019 0.041 0.063 0.084 0.033 0.064 0.093 0.122 0 0.001

Explanation / Answer

Part-1- Solution X is working as an inhibitor as the absorbance is increasing with the time increase which indicate that reaction between two solution taking palce and producing the substrate.It is an competitive inhibitor as it is decreasing the concentration of other solution while reacting with it.

Part-2- Solution Y is not working as inhibitor as the concentration of solution is not increasing this will we because it will be not reacting with the solution this is an non competitive inhibitor.

Part-3- Solution ONPG is used as positive control or we can it is an blank sample which is use to keep an test sample under observation according to which other test sample will be compare and tested.

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