A gambler enters a casino with $5. He will play until he has at least $10 or $0,
ID: 3024454 • Letter: A
Question
A gambler enters a casino with $5. He will play until he has at least $10 or $0, whichever comes first. Each bet will lose $1 with a probability of 0.75, win $1 with a probability of 0.2, and win $2 with a probability of 0.05.
a) What proportion of the time will the gambler end up with $10, and what proportion of the time will the gambler end up with $0?
b) If the gambler starts with $9, what proportion of the time will the gambler end up with $10, and what proportion of the time will the gambler end up with $0?
Please show all work and process
Explanation / Answer
a) In the second time will the gambler end up with $10
The proportion is
0.05*0.05*0.2= 0.0005
In the five time will the gambler end up with $0
The proportion is 0.1680
b) The proportion of the time will the gambler end up with $10 is 0.2
The proportion of the time will the gambler end up with $0 is 0.75^9=0.0403
Time 1 4 6 7 Time 2 3 5 6 7 8 9 Time 3 2 4 5 6 7 8 9 10 Time 4 1 3 4 5 6 7 8 9 10 Time 5 0 2 3 4 5 6 7 8 9 10Related Questions
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