A galvanic cell (battery) is represented by the shorthand below. Look up the sta

Question

A galvanic cell (battery) is represented by the shorthand below. Look up the standard half cell potentials in your textbook or on the internet. (Make sure you select the half reactions that have all the species required, and no other species.) ICI potential-1.24

            Cd(s) / Cd2+ // IO3- , H+, Cl-, ICl2- / Pt(s)

(a) Calculate Eo for this battery.

(b) What is the oxidizing agent (chemical formula of the species, not just the element)?

What is the reducing agent (chemical formula of the species, not just the element)?

            What species is/are found in the cathode compartment?

(c) Determine the overall balanced chemical equation for the battery reaction.

(d) Use Nernst eqn and the concentrations below, calculate expected cell potential.

[Cd2+] = 0.0250 M     [IO3-] = 0.100     pH = 4.00      [Cl-] = 0.500 M        [ICl2-] = 1.75 x 10-5 M

Explanation / Answer

(a) Eo = 1.24 - (-0.403) = 1.643 V

(b) Oxidizing agent : KIO3

Reducing agent : Cd

(c) Overall balanced equation,

2Cd(s) + IO3-(aq) + 2Cl-(aq) + 6H+(aq) ----> 2Cd2+(aq) + ICl2-(aq) + 3H2O

(d) E = Eo - 0.0592/n logK

= 1.643 - 0.0592/4 log[(0.025)^2 x (1.75 x 10^-5)/(0.1) x (0.5)^2 x (1 x 10^-4)^6]

= 1.382 V

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