The probability that a randomly chosen driver will be involved in an accident in
ID: 3024246 • Letter: T
Question
The probability that a randomly chosen driver will be involved in an accident in the next year is about 0.35. This is based on the proportion of millions of drivers who have accidents. "Accident" includes things like crumpling a fender in your own driveway, not just highway accidents. Carlos, David, Jermaine, Ramon, Scott, and Sean are college students who live together in an off-campus apartment. Last year, 3 of the 6 had accidents. What is the probability that 3 or more of 6 randomly chosen drivers have an accident in the same year?
Why does your calculation not apply to drivers like the 6 students?
they already had accidentssix roommates can not be considered independent they live in an off-campus apartmentnone of the above
Explanation / Answer
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 6
p = the probability of a success = 0.35
x = our critical value of successes = 3
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 2 ) = 0.647085156
Thus, the probability of at least 3 successes is
P(at least 3 ) = 0.352914844 [ANSWER]
***********************
This does not apply to them because they are not independent from each other, as they live on the same apartment.
Hence, OPTION B: six roommates can not be considered independent [ANSWER]
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.