The probability that a randomly chosen Nova Scotian male hunts is 0.21, and the
ID: 3010408 • Letter: T
Question
The probability that a randomly chosen Nova Scotian male hunts is 0.21, and the probability that they drive an all terrain vehicle (ATV) is 0.32. The probability that they do both is 0.1. Are the events ' ' hunt" and ' ' drive an ATV" disjoint (mutually exclusive)? Yes No Tries 0/1 Are the events ' ' hunt" and ' ' drive an ATV" independent? Yes No Tries 0/1 Find the probability that a randomly chosen Nova Scotian male hunts or drives an ATV. Give your answer to two places past the decimal. Tries 0/2 Find the probability that a randomly chosen Nova Scotian male drives an ATV if he hunts. Give your answer to 3 places past the decimal. Tries 0/2 Suppose you choose 3 Nova Scotian men at random. What is the probability that all three hunt? Give your answer to 3 places past the decimal. Tries 0/2 Suppose you choose 3 Nova Scotian men at random. What is the probability that none drive an ATV? Give your answer to 3 places past the decimal. Tries 0/2 Suppose you choose 3 Nova Scotian men at random. What is the probability that at least one hunts? Give your answer to 3 places past the decimal. Tries 0/2Explanation / Answer
a) ans is NO. 2 events are mutually exclusive if probability of both occuring together is 0. which is not the case here.
b)ans is NO. there is a direct formula to check it: if events A and B are independent then P(A and B)= P(A).P(B)
here, P(A and B)= 0.1 and P(A).P(B)= 0.21X0.32= 0.0672 which are not equal. so A&B are not independent.
c) P(A or B)= P(A) + P(B) - P(A and B) [where A is the event that a Nova scotian male hunts and B is the event that they drive an ATV]
therefore P(A or B)= 0.21+0.32-0.1 = 0.43
d) P(B|A) = P(AB) / P(A)
= 0.1/ 0.21
= 0.476
e) P( all 3 Nova Scotian male hunt) = 0.21 X 0.21 X 0.21 = 0.009
f)P(from the randomly choosen 3 NS male none drive an ATV)= (1-0.32)X(1-0.32)X(1-0.32)
= 0.68X0.68X0.68 = 0.314
g)P(atleast 1 out of 3 randomly choosen NS male hunt)= 1- P(none of the 3 NS male hunt)
= 1- (1-0.21)x(1-0.21)X(1-0.21)
= 1- 0.79X0.79X0.79
= 1- 0.493 = 0.507
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