DwesworK: 201813-MTH × E chegg study, I Guided 5t C Secure https:/ veb orkurrlin

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DwesworK: 201813-MTH × E chegg study, I Guided 5t C Secure https:/ veb orkurrlinted web ork2 2 1810 MIH 120 U3mw2/24/'effective ser arile & splayMode images8 showO Answers 1&user; a riley theme 8 key WesqK1AB4 A 3daVwEmore.. MAIN MENU webwork 20181o-mth120-03 I hw2 24 Hamework Sets hw2: Problem 24 Problem 24 Prev Up Next Password'Email (1p) Suppose that r)=h 1 x and that both J and h are defined for all values otr Leth 6) the blank. If you do not have enough given information to evaluate the expression, enter unknown in the blank beside the expressian. (a) h-1 (-3) = = 2 and J (0)--3. Evaluate if possible and enter the value of the expression in Problems (b)j-1(-3) = (c) h(5) = (d)3(6) = | (e) j(2) = (f) h(3(6)) = Problem 1 Problem 2 Problemi 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem1 9 Problem 10 Problem 11 Problem 12 Problem 13 Proble1 14 Problem 15 Problem 16 Problem 17 Problen 18 Problem 19 Problerm 20 h(h(2) (M-3))-1 Note: You can eam partiai credit on this problem. Preview Answers Submit Answers You have attempted this problem 6 times. Your overall recorded score is 44%. You have unlimited attempts remaining. Email instructor :17 PM Type here to search

Explanation / Answer

given j(x)=h-1(x) => h(j(x)) =x , h(6)=2 ,j(5)=-3

(a)h-1(-3) =j(-3) = unknown

(b)

j(5)=-3

=>j-1(-3)=5

(c)

h(5)= unkonown

(d)

j(6) =h-1(6) = unknown

(e)

h(6)=2

=>h-1(2)=6

j(2)=h-1(2) =6

(f)

h(j(6))

=h(h-1(6))

=6

(g)

j(h(6))=j(2)=h-1(2)=6  

(h)

(h(2))-1=(1/h(2)) = undefined

(i)

(h(-3))-1=(1/h(-3))=(1/h(j(5)))=(1/5)

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