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? scu e httpso a h aleks.com aleks in islexe/lo HgNsikr7 Bp3jHOOXBJ O 4Mr 75Nytb800a AV ett IGSa B NiOFhs40rF-Sed. Solving a percent mixture problem using a system of linear equat A chemical company mixes pure water with thelr premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 90% pure antifreeze. The company wants to obtain 180 gallons of a mixture that contains 70% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed? water: Premium antifreeze gallions Check

Explanation / Answer

Here,
Premium antifreeze solution contains 90% pure antifreeze.
It means that 100 gallons of premium antifreeze will contain 90 gallons of pure antifreeze.

To make 70% solution which means 70 gallons of pure antifreeze in 100 gallon solution.

Thus to make 180 gallons of mixture we need (70/100)*180 =126 gallons of pure antifreeze.

Thus quantity of Premium antifreeze required is 126/0.9 =140 gallons

Water required = 180-140 = 40 gallons

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