? edugen.wieyplus.com WleyPLUS Halliday, Fundamentals of Physics, 10e Calculus-b

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? edugen.wieyplus.com WleyPLUS Halliday, Fundamentals of Physics, 10e Calculus-based Physics 1& II (PH 201-2 Assignment Gradebook ORION Downloadable eTextbook nt Chapter 11, Problem 056 In a long jump, an athiete leaves the ground with an initial angular momentum that tends to rotate his body forward, threatening to ruin his counter this tendency, he rotates his outstretched arms to "take up the angular momentum (see the figure). In 0.975 s, one arm sweeps through and the other arm sweeps through 0.576 rex. Treat each arm as a thin red of mass 4.0 kg and length 0.60 m, rotating around one end. In the athlete's reference frame, what is the magnitude of the total angular momentum of the arms around the common rotation axis through the shoulders Click if you wrould like to this question

Explanation / Answer

The angular speeds of the two arms are

W1 = 0.288*2pi/0.975 =1.856 rad/s

W2 =0.576*2pi/0.975 = 3.712 rad/s

Treating each arm as a thin rod of mass 4.0 kg and length 0.60 m, the angular momenta of the two arms are

L1=mr2W1=4*0.62*1.856=2.6726 Kg-m/s

L2=mr2W2=4*0.62*3.712=5.3452 Kg-m/s

The total angular momentum about the common rotation axis though the shoulders is

L=L2-L1 =2.6726 Kg-m/s

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