Solar panel is placed on roof (well insulated). The efficiency of the panel is n

Question

Solar panel is placed on roof (well insulated). The efficiency of the panel is n=P/(aGA)=0.7-0.001(Ts)

P=Power
A=Area of panel (10m^2)
Ts=Panel Temperature

The emissivity is 0.7
The absortivity is 0.5

The total radiation on the panel is at a rate G=900 W/m^2. Determine the amount of power produced for the following conditions:

Day 1: T_infinity= 40 degrees celcius and h=10W/m^2
Day 2: T_infinity=5 degrees celcius and h=15W/m^2

Sorry if the question is phrased strangely, I tried to summarize it. Any help would be massively appreciated.

Explanation / Answer

P/aGA =0.7-0.001*Ts

a =0.5 is the absorbivity

A =10 m^2

G =900 W/m^2

1st day Ts =40 deg C

P/aGA =0.7-0.04 =0.66

P =0.66*0.5*900*10 =2970

h is the radiation emitted by an equivalent blackbody per unit area

P0 =P -e*h*A =2970-0,7*10*10 = 2900 W

e =0.7 is the emissivity

2nd day Ts =5 deg C

P/aGA =0.7-0.005 =0.695

P =0.695*0.5*900*10 =3127.5 W

P0= P-e*h*A =3127.5-0,7*15*10 =3022,5 W

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.