Fresh orange juice with 12% soluble solid content is concentrated to 60% in a mu
ID: 2975910 • Letter: F
Question
Fresh orange juice with 12% soluble solid content is concentrated to 60% in a multiple effect evaporator. To improve the quality of the final product the concentrated juice is mixed with an amount of fresh juice (cut back) so that the concentration of the mixture is 42%. Calculate how much water per hour must be evaporated in the evaporator, how much fresh juice per hour must be added back and how much final product will be produced if the inlet fee flow rate is 10,000 kg/h fresh juice. Assume steady state.Explanation / Answer
Fresh orange juice with 12% soluble solids content is concentrated to 60% in a
multiple effect evaporator. To improve the quality of the final product the
concentrated juice is mixed with an amount of fresh juice (cut back) so that
the concentration of the mixture is 42%. Calculate how much water per hour
must be evaporated in the evaporator, how much fresh juice per hour must be
added back and how much final product will be produced if the inlet feed flow
rate is 10000 kg/h fresh juice. Assume steady state.
Draw the process diagram:
Step 2
Write the total and component mass balances in envelopes I and II:
i) Overall mass balance in envelope I
10000 ¼ WþX (3:3)
ii) Soluble solids mass balance in envelope I
0:12 10000 ¼ 0:60 X (3:4)
iii) Overall mass balance in envelope II
X þ F ¼Y (3:5)
iv) Soluble solids mass balance in envelope II
0:60 X þ 0:12 F ¼ 0:42 Y (3:6)
From eqn (3.4) find X=2000 kg/h. Substituting X in eqn (3.3) and find
W=8000 kg/h. Solve eqns (iii) and (iv) simultaneously and Substitute X in
eqn (3.3) and find=1200 kg/h and Y=3200 kg/h.
Therefore 8000 kg/h of water will be evaporated, 1200 kg/h of fresh juice will be
added back and 3200 kg/h of concentrated orange juice with 42% soluble solids
will be produced.
plz rte
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