a) if the band plays 5 cities in total, how many different concert schedules can

Question

a) if the band plays 5 cities in total, how many different concert schedules can be created if there are no restriction on which cities they play?

b) if the band must play all cities in southern Alberta, then two cities in central Alberta, and finally 2 cities in northern Alberta, how many different schedules can be created?

c) if the band decides Banff and fair view should not be on the touring schedule above, how many different schedules can be created if the band plays all cities in southern Alberta, then two cities in central Alberta, and finally two cites in Northern Alberta?

Explanation / Answer

Note: I am solving based on the following information: 5 cities in Southern Alberta, 4 cities in Central Alberta, and 3 cities in Northern Alberta. a) 12C5 = 12!/(7!5!) = 792 b)(5C5)(4C2)(3C2) = 18 c)(4C4)(4C2)(2C2) = 6

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