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Dear Cramster: According to the ACT results from the 2004 ACT testing found that

ID: 2957964 • Letter: D

Question

Dear Cramster:

According to the ACT results from the 2004 ACT testing found that students had a mean reading score of 21.3 with a standard deviation of 6.0, assuming that the scores are normally distributed.

a. Find the probability that a randomly selected student has a reading ACT score less than 20.

b. Find the probability that a randomly selected student has a reading ACT score between 18 and 24.

c. Find the probability that a randomly selected student has a reading ACT score greater than 30.

d. Find the value of the 75th percentile of ACT scores.

Thank you for this consideration.

Sincerely,

Jeannette

Explanation / Answer

Given Mean =21.3

standard deviation =6.0

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a)probability ( a randomly selected student has a reading ACT score less than 20)

=P(x<20)

=P(z<20-21.3/6)

=P(z<-1.3/6)

=P(z<-0.2167)

=0.4142

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b)probability ( a randomly selected student has a reading ACT score between 18 and 24)

=P(18<=x<=24)

=P(18-21.3/6<=z<=24-21.3/6)

=P(-3.3/6<=z<=2.7/6)

=P(-0.55<=z<=0.45)

=P(z<=0.45)+P(z<=0.55)

=0.1736+0.2088

=0.3824

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c) probability ( a randomly selected student has a reading ACT score greater than 30)

=P(x>30)

=P(z>30-21.3/6)

=P(z>8.7/6)

=P(z>1.45)

=0.5-P(z<1.45)

=0.5-0.4265

=0.0735

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d) Let z* be the z score corresponding to the 75th percentile.

Let a be the value corresponding to the 75th percentile

Then P(z<z*)=0.75

From cumulative table z*=0.67

a=0.67*6+21.3

=25.32

So the value corresponding to 75th percentile is 25.32.

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