PART 1: CHOOSING THE RIGHT STATISTIC Includes parametric tests& nonparametric te
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PART 1: CHOOSING THE RIGHT STATISTIC Includes parametric tests& nonparametric tests. See Decision Tree Charts provided. Test yourself. What is the proper test statistic for each of the sample problems below? Study 1A: Study 1C: St Study 2B PART 2: USING SPSS FOR GOODNESS OF FIT CHI-SQUARE Goodness of Fit Chi-Square problem by hand. A researcher obtained a random sample of n- 60 students to determine if there were any significant preferences among 3 brands of cola. Each student tasted all three brands and then selected his/her favorite. The frequency distribution was: Brand A-28, Brand B 14, Brand C 18 Do the data indicate any preference among the three brands? You can do this problem using calculators if you have time. Is there is preference? Test with ? = 05 Write your answer using APA format: Use SPSS for this Taste Test problem. To analyze the same data in SPSS you can either enter raw data for all 60 cases- or you can enter the counts above RAW DATA Open the data file Ch17N10.sav. Run a chi-square for goodness of fit (Analyze, Nonparametric tests, Chi-square). There is only one variable (brand). The default is expecting all categories to be equal in count (or you can enter freq expected) What is the p value for this X What is the difference between the Goodness of Fit test and the Test of Independence? Independence Chi-Square problem. A psychologist interested in studying the development of romantic relationships suspects that people at different ages place emphasis on different factors when looking for a romantic partner. Two samples were collected: 30 adolescent males (age 13-15) and 30 male college students (age 19-32). Each subject was asked to identify the single most important factor determining whether he is likely to pursue a romantic relationship with a new female acquaintance. The numbers of men who choose each category are shown below. Test the researcher's hypothesis using SPSSExplanation / Answer
Part1: Chart Not provided.
Part2:
In this case, we are testing if there is any preference for particular brand.
So our NULL Hypotheses will be:
Ho = There is no preference for any brand. Students prefer each brand equally.
And, alternate Hypotheses is:
Ha = Students preferred a particular brand more tha others.
If students don't prefer any particular brand then expected frequency distribution will 20,20,20
i.e Observed Expected
brand A 28 20
brand B 14 20
brand C 18 20
For alpha = 0.05
The Chi Square value is 5.2. The p value is 0.074. The result is not significant at alpha = 0.05 since p not less than 0.05.
So, we reject alternate Hypotheses. Hence, there is no specific preference for a particluar brand.
The csv file is not given for SPSS.
-> Differenece between Independent Test and Goodness of fit test
Goodness of fit:
A goodness-of-fit test is a one variable Chi-square test. According to Steinberg (2011), “the goal of a Chi-square goodness-of-fit test is to determine whether a set of frequencies or proportions is similar to and therefore “fits” with a hypothesized set of frequencies or proportions” .
A Chi-square goodness-of-fit test is like to a one-sample t-test. It determines if a sample is similar to, and representative of, a population
Test of Independence
A test of independence is a two variable Chi-square test. Like any Chi-square test the data are frequencies, so there are no scores and no means or standard deviations. Steinberg (2011) points out, “the goal of a two-variable Chi-square is to determine whether or not the first variable is related to—or independent of—the second variable”.
Chi-square test or test of independence is similar to the test for an interaction effect in ANOVA, that asks: Is the outcome in one variable related to the outcome in some other variable”.
Independence Test
The chi-square statistic is 2.2222. The p-value is .329193. The result is not significant at p < .05.
Observed Expected Difference Difference Sq. Diff. Sq. / Exp Fr. A 28 20 8.00 64.00 3.20 B 14 20 -6.00 36.00 1.80 C 18 20 -2.00 4.00 0.20 5.200Related Questions
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