a. ASSUME YOU\'RE A MALE . Your father was ahemophiliac and your mother had norm

Question

a. ASSUME YOU'RE A MALE. Your father was ahemophiliac and your mother had normal blood clotting and was not acarrier for the hemophilia trait. What does this makeyour genotype for this trait? showwork or reasoning that leads to this conclusion. b. Once you have determined your genotype for the hemophiliatrait, construct a Punnett square that shows thepotential genotypes for your child for this trait. c. Assume that your child possesses the normal bloodclotting trait, and is not a carrier for the trait. What isthe probability of your child and his/her new spouse having a childwith hemophilia if the spouse is a hemophiliac themselves?make punnet square to show work. a. ASSUME YOU'RE A MALE. Your father was ahemophiliac and your mother had normal blood clotting and was not acarrier for the hemophilia trait. What does this makeyour genotype for this trait? showwork or reasoning that leads to this conclusion. b. Once you have determined your genotype for the hemophiliatrait, construct a Punnett square that shows thepotential genotypes for your child for this trait. c. Assume that your child possesses the normal bloodclotting trait, and is not a carrier for the trait. What isthe probability of your child and his/her new spouse having a childwith hemophilia if the spouse is a hemophiliac themselves?make punnet square to show work.

Explanation / Answer

This depends on if you are a boy or a girl. Because it issex-linked, the trait is carried on the X-chromosome. Your father,with only one X, has a bad copy of the gene and the disease. Yourmother is not a carrier, so both of ewhr X's are fine. If you are agirl, you have to get the bad X from your dad and a good X fromyour mom, so there's a one hundred percent chance that you are acarrier. If you are a boy, you have to get a good Y from your dad(you need a Y from somewhere) and any X from your mom- 100% ok/nota carrier. To draw a Punnet square, you would place two black X's on the top,and on the side, place a red X (for carrier) and a black Y). Thisleaves two all black XY's and two mixed-colored XX's.

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