1.) find the median of the two sample is combine 2.) conduct a median test to de
ID: 2908482 • Letter: 1
Question
1.) find the median of the two sample is combine
2.) conduct a median test to determine if there is a significance difference between these groups
3.) is there a significant difference between the two groups and level of aggression? if so, what is the level of significance?
4.) using the same data, conduct a Mann-Whitney U test of significance.
A standardized test is used to measure the aggression (ranging from o-300) of individuals from two groups. The following results were found: Group 1 104, 109, 127, 143, 187, 204, 209, 266, 277 Group 2 62, 82, 89, 90, 101, 106, 109, 109, 205Explanation / Answer
1.) We solve this problem using R
the median of when two sample is combine
g1=c( 104, 109, 127, 143, 187, 204, 209, 266, 277)
g2=c(62, 82, 89, 90, 101, 106, 109, 109, 205)
g=c(g1,g2)
median(g)
[1] 109
2.) Kruskal-Wallis test to conduct a median test.
g1=c( 104, 109, 127, 143, 187, 204, 209, 266, 277)
g2=c(62, 82, 89, 90, 101, 106, 109, 109, 205)
g=c(g1,g2)
gv=c(rep("g1", length(g1)), rep("g2", length(g2)))
xx=data.frame(g, gv)
kruskal.test(g~gv, data=xx)
Kruskal-Wallis rank sum test
data: g by gv
Kruskal-Wallis chi-squared = 7.2835, df = 1, p-value = 0.006959
there is a significance difference between these groups
3.) Yes, there is a significant difference between the two groups and level of aggression. The evel of significance is 0.01
4.) We can use Mann-Whitney U test OR Wilcoxon rank-sum test to compare medians.
wilcox.test(g1, g2)
Wilcoxon rank sum test with continuity correction
data: g1 and g2
W = 71, p-value = 0.007941
alternative hypothesis: true location shift is not equal to 0
Yes, there is a significance difference between these groups.
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