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Derivative and functions Two graphs are shown in Figure 2.70 and 2.71. One is te

ID: 2882003 • Letter: D

Question


Derivative and functions Two graphs are shown in Figure 2.70 and 2.71. One is temperature as a function of distance and one is illumination as a function of distance. Which is which? What is the average rate at which the temperature is changing when the illumination drops from 75% to 56%? Write the following two statements using Leibniz notation. Suppose you know that at 6 feet the instantaneous rate of change of the temperature is -4.5 degree F per foot. Suppose you also know that at 6 feet the instantaneous rate of change of illumination is -3% per foot. Using the information from part c, estimate the temperature and the illumination at 7.5 ft.

Explanation / Answer

a)

The graph of illumination function is concave up and the graph of Temperature function is concave down.

b)

When the illumination drops from 75% to 56% we need to find the rate of change in temperature during this period of time.

From the table/data given above we can see that illumination changes from 75% to 56% at d = 2 to 5 feet, so

the average rate of change in temperature = (53.5 - 47)/(2 - 5)
= 6.5/(-3) = - 2.17° F per ft

c)

Let Illumination as a function of the distance be I(d) and Temperature as a function of the distance be T(d), then

i) T(d) = T(6) + [dT/dd]d=6 *(d 6)

T(d) = T(6) - 4.5 *(d 6)

ii) Similarly as above

I(d) = I(6) - 3 *(d 6)

d)

Temperature & Illumination at 7.5 feet (using the notations of part (c) are :

T(7.5) = T(6) - 4.5 *(7.5 6) = 43.5 - 4.5*1.5

= 43.5 - 6.75 = - 36.75° F

I(7.5) = I(6) - 3 *(7.5 6) = 53 - 3*1.5

= 53 - 4.5 = 48.5%

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