A vector normal to the plane 2x - 6y + 4t - 10 = 0 is (2, 6, -4) (3, -2) (-1, -3

Question

A vector normal to the plane 2x - 6y + 4t - 10 = 0 is (2, 6, -4) (3, -2) (-1, -3, -2) Which of the following sets of information determines a plane uniquely two points two lines a point and a nonzero vector Of the planes Q: x - y + z = 0, R: 2x - 2y-2t = 4, and S: x + 2y + z = 2, which two are orthogonal? Q and S Q and S Which of the planes Q: x - y + z = 0, R: 2x - 2y-2t = 4, and S: x + 2y + z = 2 which two are parallel? Q and S Q and R S Which line is orthogonal to the plane x + y + z - 8 = 0? (2, 3, 4)+ i 1, 2, 3)where - infinity

Explanation / Answer

2) 2 lines represents the equation of plane. with two points you can just write the equation of line. with one point and one vector we can also write the equation of unique plane. so b and c

4)x-y+z = 01 and 2x-2y+2z = 4 are parallel because the coefficients of x y z are representing the vector in both plane

6)y axia

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