A variation of Russell traction ( the figure ( Figure 1 ) ) supports the lower l

Question

A variation of Russell traction ( the figure (Figure 1) ) supports the lower leg in a cast. Suppose that the patient's leg and cast have a combined mass of 16.5kgand m1 is 5.00kg .

PART A

What is the reaction force of the leg muscles to the traction?

R=________ N

PART B

What must m2 be to keep the leg horizontal?

  m2 =_______ kg

A variation of Russell traction ( the figure (Figure 1) ) supports the lower leg in a cast. Suppose that the patient's leg and cast have a combined mass of 16.5kgand m1 is 5.00kg. What is the reaction force of the leg muscles to the traction? What must m2 be to keep the leg horizontal?

Explanation / Answer

1. The reaction force of the leg muscle must be equal and opposite of the traction to be static. In that case, you must find tension T and then look at the pulley system to see just how much force is being applied to the leg.

?F=2T1-R=0

T1=m1g=49.05N

R=98.1N

2. The sum of forces in the y direction must also be equal to zero.

?F=T1+T2-(16.5 kg)g=0

T2=112.815 N

T2=m2g => m2=11.51173469387755kg

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.