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will rate lifesaver Consider the equation below. f(x) = 2 cos2x - 4 sin x, 0 le

ID: 2843313 • Letter: W

Question

will rate lifesaver

Consider the equation below. f(x) = 2 cos2x - 4 sin x, 0 le x le 2n pi Find the interval on which f is increasing. (Enter your answer in interval notation.) Find the interval on which f is decreasing. (Enter your answer in interval notation.) Find the local minimum and maximum values of f. local minimum local maximum Find the inflection points. (x,y) = ( )(smaller x-value) (x,y ) = ( )(larger x-value) Find the interval on which f is concave up. (Enter your answer in interval notation.) Find the interval on which f is concave down. (Enter your answer in interval notation.)

Explanation / Answer

increasing= (pi/2,3pi/2)

Decreasind=(0,pi/2)(3pi/2,pi)

Local maxima= 3pi/2

Local minima= pi/2

inflection point=3pi/2,pi/6,5pi/6

Concave up region=(pi/6,5pi/6),(3pi/2,0)

Concave down region= (0,pi/6),(5pi/6,3pi/2)