which holds right until he lands on the ground. He lands with a velocity of -8 m

Question

which holds right until he lands on the ground. He lands with a velocity of -8 meters per second, 1.1 seconds after starting the jump.


How high is the ledge? meters


How high is the highest point of the cats trajectory? meters

cat jumps from a ledge that is h0 meters off the ground to catch a hummingbird. While in the air, the center of mass of his motion is at a height h given by the equation h(t)=h0 + v0 middot t - 4.9 middot t2 which holds right until he lands on the ground. He lands with a velocity of -8 meters per second, 1.1 seconds after starting the jump. How high is the ledge? How high is the highest point of the cat s trajectory?

Explanation / Answer

At the Highest Point dh(t)/dt = 0

Therefore

dh(t)/dt = 0 = 0 + v0 - 9.8t

Therefore

t = 8/9.8

= 0.816 sec

As your First Answer is Right

So h0 = 2.871 m

Therefore

h(0.816) = 2.871 + 8*0.816 - 4.9*0.816^2

= 6.136m

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