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which holds right until he lands on the ground. He lands with a velocity of -7 m

ID: 2841176 • Letter: W

Question

which holds right until he lands on the ground. He lands with a velocity of -7 meters per second, 1.2 seconds after starting the jump.

a. How high is the ledge?

b. How high is the highest point of the cat

h(t)=h0 + v0 middot t - 4.9 middot t2 which holds right until he lands on the ground. He lands with a velocity of -7 meters per second, 1.2 seconds after starting the jump. How high is the ledge? How high is the highest point of the cat's trajectory? A cat jumps from a ledge that is 2.3 meters off the ground to catch a hummingbird that is hovering x meters above the ground. The highest point of the cat's trajectory is x meters from the ground, i.e. he just manages to catch the bird. He lands on the ground 1.0 second after he begins the jump. What is the value of x? How long after starting the jump does the cat reach the bird?

Explanation / Answer

I assume that a mainly vertical jump is meant. If the cat would also jump forward, there are not enough informations, e.g., on angle.

h(t) = h0 + v0*t - 4,9t^2
h(t) is 0:
0 = h0 + v0*t - 4,9t^2

determine v0:

v = v0 - gt
-7 = v0 - 9,81*1,1
v0 = -7 + 9,81*1,1
v0 = 3,79 m/s --> plug in:

- h0 = 3,79*1,1 - 5,929
h0 = 1,76 m

The height reached from the ledge is h = v0^2/2g
h = 0,732 m.
Total height reached is 2,49 m