1. A honeybee population starts with 100 bees and increases at a rate of n?(t) b

Question

1. A honeybee population starts with 100 bees and increases at a rate of n?(t) bees per week.

2. A bacteria population starts with 375 bacteria and grows at the rate of r(t)=(450)e^(6/5)t
bacteria per hour.

1. A honeybee population starts with 100 bees and increases at a rate of n?(t) bees per week. 2. A bacteria population starts with 375 bacteria and grows at the rate of r(t)=(450)e^(6/5)t bacteria per hour. a. How many bacteria will be added b. How many total bacteria will be present to the population during the first 3 hours? after 3 hours? a. What does integral 0 to 15 n'(t)dt represent? b. What does 100+ integral 0 to 15 n'(t)dt represent? 2. A bacteria population starts with 375 bacteria and grows at the rate of r(t)=(450)e^(6/5)t bacteria per hour.

Explanation / Answer

1.

In real life, integrals represent overall change. So, if the initial population is 100 and you add the change, then you will get the current population. Because the integral is from 0 to 15 it represents the population after 15 weeks

2. after 3 hours

t=180 s

so r(180)=(450)*e^(36)= (450)* 4.3112315e+15 are generated

because e^36=4.3112315e+15

total bacteria is =360+   (450)* 4.3112315e+15

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