A random sample of 80 items is drawn from a population whose standard deviation

Question

A random sample of 80 items is drawn from a population whose standard deviation is known to be = 50. The sample mean is 1formula15.mml = 810. (a) Construct an interval estimate for with 98 percent confidence. (Round your answers to 1 decimal place.) The 98% confidence interval is from ______ to ________

(b) Construct an interval estimate for with 98 percent confidence, assuming that = 100. (Round your answers to 1 decimal place.) The 98% confidence interval is from ______to _______

(c) Construct an interval estimate for with 98 percent confidence, assuming that = 200. (Round your answers to 1 decimal place.) The 98% confidence interval is from ______to______

Explanation / Answer

a)

Interval = Mean +/- Z*SD/SQRT(n)

Z for 98% interval = 2.33

a)

810 - 2.33*50/SQRT(80) to 810 + 2.33*50/SQRT(80)

797.0 to 823.0

b)

810 - 2.33*100/SQRT(80) to 810 + 2.33*100/SQRT(80)

783.9 to 836.1

b)

810 - 2.33*200/SQRT(80) to 810 + 2.33*200/SQRT(80)

757.9 to 862.1

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