A father father 2 C. neither 1.89) What proportion of the plants from the follow

Question

A father father 2 C. neither 1.89) What proportion of the plants from the following cross would be tall with yellow seeds? T-TALL, Y-YELLOW ttYy x ttyy B. 4 1.9) A child is born with cystic fibrosis. The pediatrician explains that this is an inherited genetic disorder. A. Ma ke a Punnett square to show the parents how this disorder can be inherited since neither parent has the disorder. Use the Punnett square to explain to the parents the likelihood that their next child will be affected with cystic fibrosis, also. Based on these observations, is cystic fibrosis a dominant of recessive disorder? How can you tell? B. C. amily comes into your office for genetic counseling. The husband has the allele for Huntington's Disease, a rare symptoms beginning in midlife. The wife and husband are both Rh+. The wife has Type O blood and the husband has type AB blood. Their son has Type O blood and is Rh+. 1.10) A f dominant neurodegenerative disorder that produces Based on this information, what can you tell the family about the likelihood that their son may have inherited Huntington's Disease? Where do we go from here? Well, let's see...it looks like we're going to be exploring family trees and playing genetic dice! We hurry off to CHAPTER 2 REFERENCES Christ,Shawn E."AsbjOm FOlling and the Discovery of Phenylketonuria." Journal of the History of the Neurosciences 12, no. 1 (2003): 44-54.

Explanation / Answer

1.8 the allels formed will be ty and tY from one parent. And ty from other.

The progeny will have genotype as ttyy and ttYy

So here we can see that neither offspring is tall. So the probability is 0.

1.9 as both parents are normal but the child have cystic fibrosis it means the parents are carrier because for the disease to occur in child from normal parents ,the parents must have one diseased allele which is not expressing itself.

So the disease must be a recessive disorder.

Let the normal allele as C and disease allele as c. As both parents are carrier that means both have one normal and one diseassd allele. So genotype of both parents for CF are:- Cc and Cc and gamates from both parents are C and c and the offspring would be CC,2Cc and cc

So here you can see that 25 percent of the progeny has the chance of having cystic fibrosis and 50 percent wil be carriers and 25 will be normal . So there is 25 percent chance that their next child be having cystic fibrosis.

1.10. as the husband has one allele for HD and that will pass on to 50 percent of its progeny .

HD is a autosomal dominant disease so the husband is suffered from the disease and the child may have the disease as there is 50 percent chance of passage of diseased allel to the child.

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