24. F2 plants segregate 3/4 purple and 1/4 colorless. Suppose an individual F2 p

Question

24. F2 plants segregate 3/4 purple and 1/4 colorless. Suppose an individual F2 plant that is colorless undergoes selfing, and thereby produces a large number of Fs progeny. What is the probability that BOTH colorless an purple plants will be seen among these Fs progeny? a, 0 (0%) b, 1/4 (25%), c.1/3 (33%) d. 2/3 (67%) (e.34(75%) 25. F2 plants segregate 3/4 colored and 1/4 colorless (as in the previous problem). This time, an F2 plant that is 3, purple produces a large number progeny after selfing. What is the probability that BOTH colorless and purp plants will be seen among these Fs progeny? a.a 1/4(25%) b.1/3 (33%) c. 1/2 (50%) (e)34(75%) d. 2/3 (67%) 26. Alicia and Fred are both phenotypically normal, as is one of their two children (Janelle). However, Janelle's ?-fraternal twin (Wolfgang) was born with an autosomal recessive genetic condition called phenylkettonura PKU). Alicia is currently pregnant and about to deliver their third child. What are the odds that this child w A nave PKU? a, 0 (0%) b.1/8 (12.5%) c. 1/4 (25%) (d.)1 /2 (50%) e.34(75%)

Explanation / Answer

Ans 24:

Given that F2 consists of purple and colourless in the ratio 3:1.

Thus genotype of purple in F2=Pp

Genotype of colourless =pp

On selfing a colourless F2, i.e. pp×pp,

We will get only pp in F3. Thus all will be colorful colourless. None will be purple.

Answer should be (a) 0%.

Ans 26:

Both parents are carrier, so their genotype is heterozygous. So,

Aa×Aa ,

We get 3/4 Normal (A_ ) and 1/4 affected (aa).

Thus correct choice should be

(C) 1/4 or 25%

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