Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Be sure to wateh the lab How To video on the canvas assignment page. Then use th

ID: 272633 • Letter: B

Question

Be sure to wateh the lab How To video on the canvas assignment page. Then use the link on the that same assignment page to access the online lab. From the lab website, download and print the instructions for reference as you wo through the lab. As you work through the lab fill in the table below. Use this information to answer the questions that follow. rk Table I: Record your data on the number of product molecules formed per minute obtained from the virtual lab. N Product Molecules/minute at: pH 11 Amount of Substrate Lactose) pH 3 pH 5 pH 7 pH 9 0.5 g 1.0 g 2.0 g 8 3 9 1145 1 4 35C 169 300 1 103 4.0 g 8.0 g 5. At what pH level did the maximum reaction rate occur? 6. What pH level had the worst performance? 7. Why was there no increase in the reaction rate with 8.0 g of substrate as compared to 4.0 g. of substrate? What would you need to add to see an increase in the reaction rate with 8.0 g. of substrate? 8. Consider only the experiment you conducted with 0.5 g. of lactose. What is the independent variable? What is the dependent variable?

Explanation / Answer

5) as we can see maximum product formation takes place at pH 7. Hence maximum reaction rate must be taking place at the same.

6)at pH 3 we have the worst performance.

7) This is an enzyme catalysed reaction. Enzymes have a Vmax. This is the maximum velocity that can be achieved which corresponds to the substrate concentration when all the enzyme molecules are occupied. At 4g the enzyme has reached it's maximum capacity and hence there was no increase in product. It can be increased if we increase the enzyme concentration.

8) independent variable is the pH as we vary this to find the effect on product formed which is the dependent variable.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote