A scientist recently extracted a substance from the bark of a rare tree found gr
ID: 259081 • Letter: A
Question
A scientist recently extracted a substance from the bark of a rare tree found growing in the jungle which tasted very sweet. Upon isolation, it turned out that the compound was a chemically connected chain of fructose-6-phosphate and 3-phosphoglycerate. Simple exposure to amylase from the mouth broke this molecule into its respective individual molecules. Assuming that each of these molecules could in turn enter the appropriate place in glycolysis; How many ATP molecules could be made anaerobically?How many reduced electron carriers would be made? What would be the fate of these starting molecules if oxygen were available in the metabolic process?
Explanation / Answer
Anaerobically total 5 molecules of ATP will be produced from fuctose-6-phosphate and 3-phosphoglycerate together. Because in anaerobic condition pyruvate produced in glycolysis undergoes either lactic acid fermentation or ethanol fermentation pathway. So in this case ATP production is less than aerocic glycolysis. Here net production of ATP molecules could be 3 when fructose-6-phosphate will enter glycolytic pathway and 2 when 3- phospho glycerate will enter this pathway.
No reduced electron carrier would be made anaerobically because 2 molecules of NADH produced in glycolytic pathway are utilised in fermentation processes. So there would be no net production of reduced electron carrier.
if oxygen were available in the metabolic process, then in case of fructose-6-phosphate entering glycolysis total production would be: 2 NADH directly produced in glycolysis (3 ATP each) + 3 ATP net produced in glycolysis + 8 NADH produced in TCA cycle (3 ATP each) + 2 FADH2 produced in TCA cycle (2 ATP each) + 2 ATP directly produced in the TCA cycle = 6 + 3 + 24 + 4 + 2 = 39 ATP total. In presence of oxygen, 3-phosphoglycerate entering glycolysis total production would be: 2 ATP net produced in glycolysis + 8 NADH produced in TCA cycle (3 ATP each) + 2 FADH2 produced in TCA cycle (2 ATP each) + 2 ATP directly produced in the TCA cycle = 2 + 24 + 4 + 2 = 32 ATP total. So together 1 molecule of fructose-6-phosphate and 1 molecule of 3-phosphoglycerate would produce 12+10= 22 molecules of reduced electron carriers and 38+32 = 70 molecules of ATP.
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