6. A true-breeding, purple-flowered, yellow pea plant (PPYY) is crossed to a whi

ID: 256960 • Letter: 6

Question

6. A true-breeding, purple-flowered, yellow pea plant (PPYY) is crossed to a white-flowered, green pea plant (ppyy). A. Write out the parental cross.

B. What gametes can be produced by each parent?

C. What is the genotype of the F1 generation? What is the Phenotype?

D. What are the possible gametes that can be produced from each plant F1 plant?

E. An F1 plant is allowed to self fertilize (F1 X F1). Draw a Punnet square to show the possible genotypes of the offspring in the F2 generation.

F. What phenotypes are possible in the F2 generation? What is the probability of getting each of the phenotypes in the F2 generation?

A. PPYY x ppyy

B. Gametes from PPYY - All PY

Gametes from ppyy - All py

C. Punnett square analysis:

All F1 offspring are heterozygous and hence show the dominant phenotype. So all F1 offspring will have purple flowers and yellow pea.

D. Possible gametes of PpYy are - PY, pY, Py, and py

E. PpYy x PpYy

Punnett square analysis:

F. The possible phenotypes in the F2 generation are:

The probability of getting purple flower, yellow pea plant is : (9/16) x 100 % = 56.25%

The probability of getting purple flower, green pea plant is : (3/16) x 100 % = 18.75%

The probability of getting white flower, yellow pea plant is : (3/16) x 100 % = 18.75%

The probability of getting white flower, green pea plant is : (1/16) x 100 % = 6.25 %

PY PY PY PY py PpYy PpYy PpYy PpYy py PpYy PpYy PpYy PpYy py PpYy PpYy PpYy PpYy py PpYy PpYy PpYy PpYy

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