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5. Cells that are growing/proliferating need to produce NADPH for biomolecular s

ID: 252669 • Letter: 5

Question

5. Cells that are growing/proliferating need to produce NADPH for biomolecular synthesis. One synthesis is via the oxidative pentose-phosphate pathway (OPPP), which is To fuel the OPPP pathway, glucose units (in the form of glucose-6-phosphate) are the OPPP. The products of the OPPP, in addition to NADPH, are circled in the figure. These products can be outlined in the accompanying figure. directly inserted back into glycolysis and be aerobically oxidized. shuttled from glycolysis into How many molecules of ATP (theoretical maximum) are lost when glucose, diverted from glycolysis to the OPPP, is used to generate 6 molecules of NADPH? EXPLAIN your answer (Note in the figure below the number of lines in an arrow represents the number of molecules reacting in one turn of the pathway so as to convert 3 G6P to 3 CO2, 2 F6P, and 1 GAP. (4 points) NADPH+H NADPH + Co P NADP ??-c-a H-C-OH ?? ? ??? Glucose-6 phosphate (G6P) ? 6-phospho. H_C_0H gluconate beoPO OH H ??? 6-Phosphoglucono glucose- glucono- OH dehydrogenase -dehydro- 6-Phospho genase Ribulose-5- gluconate ?-lactone phosphate (RuSP) H-C-OH H-C-OH 2- Ribose-5 phosphate (RSP) CH2???? Glyceraldehyde Sedoheptulose-7 -phosphate phosphate (57P) ??-?--H rib 7 transaldolase CH20PO Xylulose-5 phospbate (KuSP) 'CH2OH ?-?-?? H-C-oOH CMgoPo,?- CH2OPO Fructose-6 Erythrose-4- Fructose-6 Glyceraldehyde phosphate 3-phosphate (F6P)(GAP) (F6P) phosphate (E4P) Figure 1430 Fundamentals of Biochemistry, 2le © 2006 John Wiley & Sons

Explanation / Answer

Glucose + ATP----hexokinase------Glucose 6 P + ADP + Pi

For one Glucose 6 Phosphate production we need one ATP molecule it enter into OPPP pathway and produce 2 NADPH.

So for 6 NADPH three Glucose 6 Phosphate required So 3 ATP are involved.

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