a) What fraction of the total distance is traveled at constant speed? b) What to

Question

a) What fraction of the total distance is traveled at constant speed?

b) What total time (in seconds) is required for the trip?

A spaceship ferrying workers to Moon Base I takes a straight-line path from the earth to the moon, a distance of 384000 km. Suppose it accelerates at an acceleration 19.4 m/s2 for the first time interval 16.0 min of the trip, then travels at constant speed until the last time interval 16.0 min , when it accelerates at-19.4 m/s2 , just coming to rest as it reaches the moon. 1 mi f th en traveln at constant speed accelerates at 194 m/s2 just coming to rest

Explanation / Answer

distance tarvelled with accelartion in 16 minute

S=ut +0.5at2

=0 +0.5*19.4(16*60)2=8939520 metre=8939.520 Km

remaining distance wtravelled with constant speed =384000-8939.520=375060.48Km

nowvelocity after accelartion of 16 minute

v=u+at=0+19.4*16*60=18624m/s=18.624Km/s

now time taken to travel remaining distance=375060.48/18.624=20138.5567sec

so toatal time=16*60+20138.5567sec=21098.5567s

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