The point charges in the figure below are located at the corners of an equilater

Question

The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where qb = +22.0 µC and

qc = ?3.50 µC. (Assume that the +x-axis is directed to the right.)

The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where qb = +22.0 C and qc =3.5C. (Assume that the +x-axis is directed to the right.) la lc (a) Find the electric field at the location of qa magnitude direction X(counterclockwise from the +x-axis) (b) what is the force on qa, given that qa = +1.50 nC? magnitude direction X(counterclockwise from the +x-axis) Enter a number

Explanation / Answer

field at qa = due to qb + due to qc

= [9 x 10^9 x 22 x 10^-6 / 0.25^2](-cos60i -sin60j) + [ 9 x 10^9 x 3.50 x 10^-6 / 0.25^2](-cos60i + sin60j)

= -1836000i - 2307091.67j

a) magnitude = sqrt(1836000^2 + 2307091.67^2) = 2948485.71 N/C

direction = 180 + tan^-1(j/i) = 231.49 deg

b) F = qE

magnitude = 1.50 x 10^-9 x 2948485.71 = 0.0044 N

direction = same as E = 231.49 deg

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